![e ) If the constant term of the binomial expansion ( left( 2 x - frac { 1 } { x } right) ^ { n } ) is ( - 160 , ) then ( n ) is equal to ( ( A ) ) ( ( B ) 6 ) ( ( mathrm { C } ) 8 ) ( ( D ) 10 ) e ) If the constant term of the binomial expansion ( left( 2 x - frac { 1 } { x } right) ^ { n } ) is ( - 160 , ) then ( n ) is equal to ( ( A ) ) ( ( B ) 6 ) ( ( mathrm { C } ) 8 ) ( ( D ) 10 )](https://toppr-doubts-media.s3.amazonaws.com/images/2733649/51fdb9a9-00b0-483d-b7bf-453701f2fa82.jpg)
e ) If the constant term of the binomial expansion ( left( 2 x - frac { 1 } { x } right) ^ { n } ) is ( - 160 , ) then ( n ) is equal to ( ( A ) ) ( ( B ) 6 ) ( ( mathrm { C } ) 8 ) ( ( D ) 10 )
![Pascal's Triangle and the Binomial Theorem (x + y) 0 = 1 (x + y) 1 = 1x + 1y (x + y) 2 = 1x 2 + 2xy + 1y 2 (x + y) 3 = 1x 3 + 3x 2 y + 3xy 2 +1 y 3 (x. - ppt download Pascal's Triangle and the Binomial Theorem (x + y) 0 = 1 (x + y) 1 = 1x + 1y (x + y) 2 = 1x 2 + 2xy + 1y 2 (x + y) 3 = 1x 3 + 3x 2 y + 3xy 2 +1 y 3 (x. - ppt download](https://images.slideplayer.com/26/8787879/slides/slide_10.jpg)
Pascal's Triangle and the Binomial Theorem (x + y) 0 = 1 (x + y) 1 = 1x + 1y (x + y) 2 = 1x 2 + 2xy + 1y 2 (x + y) 3 = 1x 3 + 3x 2 y + 3xy 2 +1 y 3 (x. - ppt download
Without expanding, what is the constant term and middle term for the binomial expansion of (x/2-√2/x^3) ^10? - Quora
Without expanding, what is the constant term and middle term for the binomial expansion of (x/2-√2/x^3) ^10? - Quora
![The sum of the binomial coefficients of (2x 1/x)^n is equal to 256. The constant term in the expansion is - A.1120 B.2110 C.1210 S.none Correct answer is 'A'.could you explain me The sum of the binomial coefficients of (2x 1/x)^n is equal to 256. The constant term in the expansion is - A.1120 B.2110 C.1210 S.none Correct answer is 'A'.could you explain me](https://edurev.gumlet.io/ApplicationImages/Temp/510443_a7a35946-406d-42f6-9723-18ef7d830dd9_lg.png?w=360&dpr=2.6)
The sum of the binomial coefficients of (2x 1/x)^n is equal to 256. The constant term in the expansion is - A.1120 B.2110 C.1210 S.none Correct answer is 'A'.could you explain me
![find the constant term in expansion of [(2/rootx)+3x]^12 - Maths - Binomial Theorem - 13106335 | Meritnation.com find the constant term in expansion of [(2/rootx)+3x]^12 - Maths - Binomial Theorem - 13106335 | Meritnation.com](https://s3mn.mnimgs.com/img/shared/content_ck_images/ck_5bb0afa09b76f.jpg)
find the constant term in expansion of [(2/rootx)+3x]^12 - Maths - Binomial Theorem - 13106335 | Meritnation.com
If the constant term in the binomial expansion of (√x - (k/x^2))10 is 405, then |k| equals : (1) 2 (2) 1 (3) 3 - Sarthaks eConnect | Largest Online Education Community
![Topic(s) : BINOMIAL THEOREM [Maximum mark: 6] Consider the expansion of The constant term the cor is 5103. Consider the expansion of Find the possible values of p. Topic(s) : BINOMIAL THEOREM [Maximum mark: 6] Consider the expansion of The constant term the cor is 5103. Consider the expansion of Find the possible values of p.](https://toppr-doubts-media.s3.amazonaws.com/images/4520939/4f57e959-a972-4b19-aaa5-0ecf310b8c5f.jpg)
Topic(s) : BINOMIAL THEOREM [Maximum mark: 6] Consider the expansion of The constant term the cor is 5103. Consider the expansion of Find the possible values of p.
![Additional Math – Binomial Theorem – No term independent of x – Tuition with Jason – Math Specialist Additional Math – Binomial Theorem – No term independent of x – Tuition with Jason – Math Specialist](https://i0.wp.com/www.tuitionwithjason.sg/wp-content/uploads/2018/08/a-math-binomial-theorem-explain-why-there-is-no-term-independent-of-x.png?fit=655%2C263&ssl=1)